22 Jun 0.122 meters per second The plate’s acceleration is ##9.8
0.122 meters per second The plate’s acceleration is ##9.8 m/(s^2)##. So the balls must increase the plate’s speed by ##9.8m/s## so the plate will be balanced. That means that each ball must increase the plate’s speed in ##(9.8)/(40)=0.245 m/s##. As the total momentum is conserved in a rebound if balls have a velocity ##v## the conservation of momentum is expressed as follows: ##0.2*v## (when the balls go up) ##= 0.2*0.245+(-v)*0.2## (the momentum of the plate going up plus the momentum of the ball going down). Then ##v=0.2*0.245/0.4 = 0.122##.
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