24 Jun ##23## is the smaller number. Let the first number be ##x##
##23## is the smaller number. Let the first number be ##x## and the second number be ##y##. In this case the simultaneous equations would be: ##x+y=69## ##x-y=23## Let’s label the first equation as equation 1 and the second one as equation 2. Now we want to find only one unknown at a time so we’ll use substitution to get only one unknown at a time. Let’s do ##y## first. From equation 2 ##x=23+y## Let this be equation 3. Now we shall substitute the ##x## in equation 1 with Equation 3. ##=> (23+y)+y=69## ##2y=69-23## ##2y=46## ##y=23## Now that we have one unknown let’s solve for the other by substituting this value of ##y## into equation 1. ##x+23=69## ##x=46## ##:.##the two numbers are ##46## and ##23## with ##23## being the smaller number.
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