19 Jun ##y^8/x^2## We can use exponent rules to simplify this expre
##y^8/x^2## We can use exponent rules to simplify this expression. Taking a look at the original function; ##(x^-2y^-4x^3)^-2## We can see that there are two ##x## terms inside of the parenthesis. Lets combine those first. If we multiply two terms with exponents the exponents add in other words; ##x^a xx x^b = x^(a+b)## Applying this to our case we get; ##(x^((3-2))y^-4)^-2## ##(x^1y^-4)^-2## Now lets take a look at the exponent outside the parenthesis. Whenever we raise an exponent term to an exponent we multiply the exponents. ##(x^a)^b = x^((a)(b))## In our case raising both the ##x## term and the ##y## term to ##-2## we get; ##x^((-2)(1))y^((-2)(-4))## ##x^-2y^8## Now we have one negative exponent and one positive exponent. We need to convert the ##x## term to a positive exponent. To do that we will invert the term. ##x^-a = 1/x^a## So to get rid of the ##-## we will move the ##x## term to the denominator. ##y^8/x^2##
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