19 Jun (A) X-intercept is a point where a graph intersects the X-ax
(A) X-intercept is a point where a graph intersects the X-axis that is a point with coordinates ##(a0)## that satisfies our equation when we substitute ##x=a## and ##y=0##. Therefore we just have to find ##a## if ##0=1/2(a-8)^2+2## This equation obviously has no real solutions because ##1/2(a-8)^2 >= 0## because it’s a square of some number multiplied by a positive constant and therefore ##1/2(a-8)^2+2 > 0## and there are no such values of ##a## when the expression ##1/2(x-8)^2+2## equals to ##0##. (B) Axis of symmetry of a canonical parabola ##y=x^2## is the Y-axis. The parabola ##y=1/2x^2## differs from a canonical one only by a multiplier ##1/2## which just squeezes the parabola towards the X-axis by a factor of ##2## without changing its axis of symmetry. Subtracting a positive constant from an argument ##x## in the equation of any function ##y=F(x)## shifts the graph to the right by the value of this constant. Therefore the axis of symmetry of ##y=1/2(x-8)^2## is a straight line parallel to the Y-axis and intersecting the X-axis at point ##x=8##. The equation of this line is ##x=8## (independent of ##y##). Adding ##2## to a function shifts the graph upwards without changing it’s axis of symmetry. So parabola ##1/2(x-8)^2+2## has a line ##x=8## as the axis of symmetry. (C) The minimum point of a canonical parabola ##y=x^2## is a point ##(00)##. After squeezing it by a factor of ##2## the minimum point does not change its position. After subtracting ##8## from the argument the whole graph shifts to the right by ##8## and the minimum point shifts by ##8## as well taking a position ##(80)##. After that we add ##2## to a function which shifts the graph upwards by ##2## so the minimum point shifts to ##(82)##. (D) Y-intercept is a point on the Y-axis where the graph intersects this axis. This is a value of a function when an argument equals to zero. Substitute ##x=0## in the function: ##y=1/2(0-8)^2+2## from which we derive ##y=34##. Therefore a point ##(034)## is a Y-intercepts. Let’s illustrate it graphically: graph{1/2(x-8)^2+2 [-1 20 -10 40]} On the above graph you see that there is no X-intercepts the axis of symmetry is a line ##x=8## the minimum point is ##(82)## and the Y-intercepts is ##34##.
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