23 Jul WHAT WOULD BE THE EQUILIBRIUM CONCENTRATION OF GLUCOSE-6-PHOSPHATE ACCORDING TO THE ABOVE DATA?
phosphate+H2 Show more The first reaction in glycolysis is the phosphorylation of glucose: Pi+glucoseglucose6phosphate+H2O This is a thermodynamically unfavorable process with G=+13.8kJ/mol. Part A In a liver cell at 37 C the concentrations of both phosphate and glucose are normally maintained at about 5 mM each. What would be the equilibrium concentration of glucose-6-phosphate according to the above data? Express your answer to two significant figures and include the appropriate units. Equilibrium concentration = SubmitMy AnswersGive Up Part B This very low concentration of the desired product would be unfavorable for glycolysis. In fact the reaction is coupled to ATP hydrolysis to give the overall reaction ATP+glucoseglucose6phosphate+ADP+H+ What is G for the coupled reaction? Express your answer to three significant figures and include the appropriate units. G = SubmitMy AnswersGive Up Part C If in addition to the constraints on glucose concentration listed previously we have in the liver cell ATPconcentration = 3 mM and ADP concentration = 1 mM what is the theoretical concentration of glucose-6-phosphate at equilibrium at pH=7.4 and 37 C? Express your answer to three significant figures and include the appropriate units. Theoretical concentration = Show less
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